__CONVERSION__

We have converted **normal Km to
Chotu Km which are 0.463831 of the normal kilometer length** but we have not
converted time to distance or vice versa. We have kept the divisions distance
the same 24 x 60 x 60 **(for easy understanding)** whereas we could very well
have kept them as 25 x 40 x 40 (*See Page 11*) and 28 x 70 x 70 divisions
(*See Page 26*).

__Note
10:__

Now we take the distance piece with a dial diameter of 35.4 mm and a circumference of 111.3 mm (See Page 15 Fig 8) and place it within a spiral (See Page 33 Fig 18) giving 00000 to 43200 Chkm for the inner (i.e. ½ L = E) and 43200 to 86400 for the outer (i.e. up to 1L = 2E). Therefore we have 1L divided by 2, which is equal to 1 E, 1E divided by 12 we get 1B (43200/12 = 3600 Chkm), 1B divided by 60 = 1 R, 1R divided by 60 we get 1P.

From Page 16, see fig.9 G-G’ we see 60p x 12 = 720 = 1M (M = 1Measure), 720 x5

= 3600 P or [720x5 = (60x12) x5 =
60 x 12 x5 = 60 x 60] = 3600P and also 3600P x 12

= 43200 Chkm.

Therefore 1 L = 86400 Chkm

1E = 43200 Chkm

1B = 3600 Chkm

1 M = 720 Chkm = (60 x 12 Chkm)

1 R = 60 Chkm

1 P = 1 Chkm

1R x 1M = 60 Chkm x (60 x 12) Chkm = (60 x 60 Chkm) x 12

= 3600 Chkm x 12 =1 E = 43200 Chkm, and

2 x E = 2 x 43200 = L = 86400 Chkm.

Earth’s ORBIT around the Sun_{
E}O®_{S} Moon’s Orbit
around the Earth = _{M}O®_{E }

**Speed, Velocity and
Acceleration**

1. Let us think of 3 teethed (gears) wheels in mesh with each
other such that ** (See Fig.23.)** Wheel A has 60 teeth, Wheel B 30
teeth and Wheel C 120 teeth .It is clear that when Wheel A makes a complete
Revolution all its teeth move i.e. its 60 teeth move 60 teeth out of 120 teeth
of Wheel C which means 60/120 = ½. So when A Revolves 1 full Revolution, C
Revolves only ½ a Revolution i.e. the

**(46)**